# Consider a proton with a 6.6 fm wavelength. What is the velocity of the proton in meters per second? Assume the proton is nonrelativistic. (1 femtometer = 10^(-15) m)

Consider a proton with a 6.6 fm wavelength. What is the velocity of the proton in meters per second? Assume the proton is nonrelativistic. (1 femtometer $={10}^{-15}$ m)
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Gabriella Hensley
Wavelength , $\lambda =6.6fm=6.6×{10}^{-15}m$
To find = Velocity of proton
We can calculate the velocity using :
De Broglie wave equation :
$\lambda =\frac{h}{mv}$ , where h is Planck's constant and m is proton's mass .
Solving for v , we get :
$v=\frac{h}{m\lambda }$, where $m=1.67×{10}^{-27}kg,h=6.626×{10}^{-34}Js$
Substituting the given values ,we get :
$v=\frac{6.626×{10}^{-34}}{1.67×{10}^{-27}×6.6×{10}^{-15}}$
$v=0.6×{10}^{8}$
$v=6×{10}^{7}$ m/s
Hence ,the velocity of the proton is $v=6×{10}^{7}$ m/s .