Find the equation of the line that passes through (9,1) and is perpendicular to the line that passes through the following points: (7,−3),(6,3)

emmostatwf
2022-10-03
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Maddox Koch

Answered 2022-10-04
Author has **7** answers

The slope of the line passing through (7,-3) , (6,3) is $\frac{3+3}{6-7}=-6$

So the slope of the perpendicular line passing through (9,1) is $\frac{1}{6}$ since the product of slopes of perpendicular lines is -1. Hence the equation of the line passes through (9,1) is $y-1=\frac{1}{6}(x-9)$ or $y=\frac{1}{6}\cdot x-\frac{1}{2}$

So the slope of the perpendicular line passing through (9,1) is $\frac{1}{6}$ since the product of slopes of perpendicular lines is -1. Hence the equation of the line passes through (9,1) is $y-1=\frac{1}{6}(x-9)$ or $y=\frac{1}{6}\cdot x-\frac{1}{2}$

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