Geometric distribution-Calculation of probability of success

I saw a question on geometric distribution.

A bank is reviewing its telephone banking division and tries to find how soon/easily a customer can talk to a phone-banking officer. When a customer calls, the phone rings for 12 times before getting to the call-back services.

An experiment is conducted with 5 people and the number of calls made to reach the banking officer is recorded.(they are asked to retry if the call-back service is reached).The number of calls made to reach the banking officer is recorded for each participant and are as follows:

- 5

- 0

- 1

- 0

- 0

In this experiment, what is the probability of success(p of a geometric distribution)? Is it 1/2 (because it is equally likely to reach the officer as reaching the call back service) or is it 3/5( 3 participants out of 5 have reached the bank officer in the first attempt without any failure) ?

Geometric distribution used for modeling the number of failures until the first success:

$Pr(Y=k)=p\cdot (1-p{)}^{k}\text{}\text{where}\text{}k=1,2,3\text{}\text{and}\text{}p=$ probability of success

I saw a question on geometric distribution.

A bank is reviewing its telephone banking division and tries to find how soon/easily a customer can talk to a phone-banking officer. When a customer calls, the phone rings for 12 times before getting to the call-back services.

An experiment is conducted with 5 people and the number of calls made to reach the banking officer is recorded.(they are asked to retry if the call-back service is reached).The number of calls made to reach the banking officer is recorded for each participant and are as follows:

- 5

- 0

- 1

- 0

- 0

In this experiment, what is the probability of success(p of a geometric distribution)? Is it 1/2 (because it is equally likely to reach the officer as reaching the call back service) or is it 3/5( 3 participants out of 5 have reached the bank officer in the first attempt without any failure) ?

Geometric distribution used for modeling the number of failures until the first success:

$Pr(Y=k)=p\cdot (1-p{)}^{k}\text{}\text{where}\text{}k=1,2,3\text{}\text{and}\text{}p=$ probability of success