Based on the estimates log(2) = .03 and log(5) = .7, how do you use properties of logarithms to find approximate values for log(0.25)?

elisegayezm

elisegayezm

Answered question

2022-09-29

Based on the estimates log ( 2 ) = .03 and log ( 5 ) = .7, how do you use properties of logarithms to find approximate values for log ( 0.25 )?

Answer & Explanation

blikath3

blikath3

Beginner2022-09-30Added 7 answers

Firstly, fixing the typo in the question: log ( 2 ) 0.3.
log ( 0.25 ) = log ( 1 4 ) = log ( 1 2 2 ) = log ( 2 2 )
= 2 log ( 2 ) 2 × 0.3 = 0.6
Incidentally, do you know why log ( 2 ) 0.3?
10 × log ( 2 ) = log ( 2 10 ) = log ( 1024 ) log ( 1000 ) = log ( 10 3 ) = 3
So basically it's because 2 10 10 3

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