# Two forces act on a 2.55 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced (4.05 hat(i) – 3.30 hat(j)) m. Write th second force in unit vector notation.

Two forces act on a 2.55 kg object, the gravitational force and a second, constant force. The object starts from rest and in 1.20 s is displaced $\left(4.05\stackrel{^}{i}-3.30\stackrel{^}{j}\right)$ m. Write second force in unit vector notation.
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Given:
m =2.55 Kg
t =1.20 Sec
$d=4.05\stackrel{^}{i}-3.30\stackrel{^}{j}$
To find:
Force acting on the given mass.
Solution:
Gravitational force =
Direction would be - $\stackrel{^}{j}$
Constant force acting on
As gravitational force acting in downward direction constant force should be in positive x direction as shown in displacement.
Only x direction displacement is to be taken here.
$\text{velocity}=\frac{\text{displacement}}{\text{time}}\phantom{\rule{0ex}{0ex}}\text{velocity}=\frac{4.05\stackrel{^}{i}}{1.20}=3.375\stackrel{^}{i}\phantom{\rule{0ex}{0ex}}\text{acceleration}=\frac{\text{velocity}}{\text{time}}\phantom{\rule{0ex}{0ex}}\text{acceleration}=\frac{3.375}{1.20}\stackrel{^}{i}=2.81\stackrel{^}{i}$
Force is the product of mass and acceleration.

direction is positive x direction