A particle with a charge of 5 mu C is moving at 3 * 10^6 m/s perpendicularly through a magnetic field with a strength of 0.06T. What is the magnitude of the force on the particle?

clovnerie0q 2022-10-02 Answered
A particle with a charge of 5 μ C is moving at 3 10 6   m / s perpendicularly through a magnetic field with a strength of 0.06T. What is the magnitude of the force on the particle?
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Answers (1)

Salma Baird
Answered 2022-10-03 Author has 8 answers
Charge of the particle (q) = 5 × 10 6   C
Velocity of the particle (v) = 3 × 10 6   m / s
Magnetic field ( B ) = 0.06 T
Magnitude of force
F = q ( v × B ) F = q v B sin 90 0 F = 5 × 10 6 × 3 × 10 6 × 0.06 F = 0.9   N e w t o n
So,magnitude of force = 0.9 Newton
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