We check 15 bananas. Six of the bananas are bruised.
Recall the Definition of Probability:
If all outcomes of an experiment are equally likely, then the probability is given by,

Probability of an event or = ‘Number of favorable outcomes/Total number of possible outcomes

(a) From the given statement the total number of bananas are 15 and 6 number of bananas are bruised.

Therefore, the experimental probability that « banana. is bruised is

\(\displaystyle\frac{{6}}{{15}}=\frac{{2}}{{5}}\)

(b) Also, there are 15 — 6 = 9 number of bananas are not bruised. Thus, the experimental probability that « banana is not bruised is

\(\displaystyle\frac{{9}}{{15}}=\frac{{3}}{{5}}\)

\(\displaystyle{a}.\frac{{2}}{{5}}{b}.\frac{{3}}{{5}}\)

Probability of an event or = ‘Number of favorable outcomes/Total number of possible outcomes

(a) From the given statement the total number of bananas are 15 and 6 number of bananas are bruised.

Therefore, the experimental probability that « banana. is bruised is

\(\displaystyle\frac{{6}}{{15}}=\frac{{2}}{{5}}\)

(b) Also, there are 15 — 6 = 9 number of bananas are not bruised. Thus, the experimental probability that « banana is not bruised is

\(\displaystyle\frac{{9}}{{15}}=\frac{{3}}{{5}}\)

\(\displaystyle{a}.\frac{{2}}{{5}}{b}.\frac{{3}}{{5}}\)