# If F in k[x_0,...,x_n] is homogeneous and F=x^alpha_0 G (where x_0 does not divide G) then beta*alpha(F)=G.

If $F\in k\left[{x}_{0},...,{x}_{n}\right]$ is homogeneous and $F={x}_{0}^{\alpha }G$ (where ${x}_{0}$ does not divide G ) then $\beta \circ \alpha \left(F\right)=G$
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trutdelamodej0
Let's write $G=\sum _{|\alpha |=d\left(G\right)}{a}_{\alpha }{x}^{\alpha }$, we can do so as G is homogeneous. Now we have
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