# Solve: 1/root(3)(4x)

Solve:
$\frac{1}{\sqrt[3]{4x}}$
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Solution:
$\frac{1}{\sqrt[3]{4x}}=\frac{1}{\left(4x{\right)}^{1/3}}\phantom{\rule{0ex}{0ex}}\frac{1}{\sqrt[3]{4x}}=\frac{1}{\left(4x{\right)}^{1/3}}\phantom{\rule{0ex}{0ex}}=\left(4x{\right)}^{-\frac{1}{3}}$