How do I rationalize the following fraction: $\frac{1}{9\sqrt[3]{9}-3\sqrt[3]{3}-27}$?

As the title says I need to rationalize the fraction: $\frac{1}{9\sqrt[3]{9}-3\sqrt[3]{3}-27}$. I wrote the denominator as: $\sqrt[3]{{9}^{4}}-\sqrt[3]{{9}^{2}}-{3}^{3}$ but I do not know what to do after. Can you help me?

As the title says I need to rationalize the fraction: $\frac{1}{9\sqrt[3]{9}-3\sqrt[3]{3}-27}$. I wrote the denominator as: $\sqrt[3]{{9}^{4}}-\sqrt[3]{{9}^{2}}-{3}^{3}$ but I do not know what to do after. Can you help me?