Is this summation solvable? ${S}_{n}=\sum _{i=2}^{n}{\mathrm{log}}_{i}(n)$

Is it possible to solve a summation with a variable base of log?

${S}_{n}=\sum _{i=2}^{n}{\mathrm{log}}_{i}(n)$

Should I use the derivative of ${\mathrm{log}}_{i}(n)$

Is it possible to solve a summation with a variable base of log?

${S}_{n}=\sum _{i=2}^{n}{\mathrm{log}}_{i}(n)$

Should I use the derivative of ${\mathrm{log}}_{i}(n)$