Write an equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5)

Nathanial Levine
2022-09-29
Answered

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Ricky Lamb

Answered 2022-09-30
Author has **7** answers

I would use the relationship:

$y-{y}_{0}=m(x-{x}_{0})$

Where m is the slope and $x}_{0},{y}_{0$ are the coordinates of your point.

The slope m of the perpendicular is given as: $m=-\frac{1}{{m}_{1}}$ where $m}_{1$ is the slope of your given line:

Your line can be written (isolating y):

$y=\frac{x}{5}+2$ which has slope $m}_{1}=\frac{1}{5$ (the coefficient of x).

So, the slope of the perpendicular will be:

m=−5

Finally you get:

$y-5=-5(x-2)$

$y=-5x+10+5$

$y=-5x+15$

$y-{y}_{0}=m(x-{x}_{0})$

Where m is the slope and $x}_{0},{y}_{0$ are the coordinates of your point.

The slope m of the perpendicular is given as: $m=-\frac{1}{{m}_{1}}$ where $m}_{1$ is the slope of your given line:

Your line can be written (isolating y):

$y=\frac{x}{5}+2$ which has slope $m}_{1}=\frac{1}{5$ (the coefficient of x).

So, the slope of the perpendicular will be:

m=−5

Finally you get:

$y-5=-5(x-2)$

$y=-5x+10+5$

$y=-5x+15$

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