What are the asymptotes for y=−4/x+2 and how do you graph the function?

st3he1d0t 2022-09-30 Answered
What are the asymptotes for y = - 4 x + 2 and how do you graph the function?
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Answers (1)

graulhavav9
Answered 2022-10-01 Author has 14 answers
The asymptotes are at x=−2 and y0, this is because when x=−2 the denominator would equal 0 which cannot be solved. The y=0 asymptote is caused because as x , the number will get so small and close to 0, but never reach 0.

The graph is that of y = 1 x but shifted to the left by 2, and flipped in the x-axis. The curves will be more rounded as the numerator is a larger number.

Graph of y = 1 x
graph{1/x [-10, 10, -5, 5]}

Graph of y = 4 x
graph{4/x [-10, 10, -5, 5]}

Graph of y = - 4 x
graph{-4/x [-10, 10, -5, 5]}

Graph of y = - 4 x + 2
graph{-4/(x+2) [-10, 10, -5, 5]}
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