Consider the curve given by the equation xy - 3x + 2y = -2. Find the equation of the tangent in the point (2,1). So through implicit differentiation I've found that (if I'm correct) y' = (1-y)/(x-2) How do I proceed to find the tangent line since there are still 2 variables in the function?

sengihantq

sengihantq

Answered question

2022-09-30

Consider the curve given by the equation xy - 3x + 2y = -2. Find the equation of the tangent in the point (2,1).
So through implicit differentiation I've found that (if I'm correct) y' = (1-y)/(x-2)
How do I proceed to find the tangent line since there are still 2 variables in the function?

Answer & Explanation

Marcel Mccullough

Marcel Mccullough

Beginner2022-10-01Added 11 answers

Note that if we have
x y 3 x + 2 y = 2
then after differentiation we get
y + x y 3 + 2 y = 0 x y + 2 y = 3 y y ( x + 2 ) = 3 y y = 3 y x + 2
Edit: So to find the tangent line, first you need the slope of the tangent line at the point (2,1). You do that by plugging in the coordinates in the derivative expression we found, so y at (2,1) is:
y = 3 1 2 + 2 = 1 2
You know the slope, and you know one point on the tangent line (namely, (2,1)) so you can find the equation of the line from here.

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