The larger of 2 numbers is 11 less than 3 times the smaller. The sum is 69. I need to know what are the numbers?

seguitzi2
2022-09-27
Answered

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tona6v

Answered 2022-09-28
Author has **6** answers

Let the no.s be x and 3x−11

According to the question,

x+3x−11=69

4x−11=69

4x=69+11

4x=80

x=80/4

x=20

According to the question,

x+3x−11=69

4x−11=69

4x=69+11

4x=80

x=80/4

x=20

Tatiana Cook

Answered 2022-09-29
Author has **3** answers

Let's have the smaller number be represented by a variable x and the larger number by y. Our first step is to create numerical equations that represent the numbers. The larger number is 11 less than the smaller number if the smaller number is multiplied by 3. Therefore, the first equation is: y=3x−11. Our second equation will be x+y=69 since the sum is 69.

Our next step is to substitute one equation into another. That way, we can form an equation with only one variable in it. Let's put our first equation into the second one:

x+(3x−11)=69

From here, all we have to do is simplification:

x+3x−11=69

4x−11=69

4x=80

x=20

We have our smaller number, 20. To find the larger number, plug the smaller number into our second equation and solve for y:

20+y=69

y=49

We now have our larger number 49.

Our next step is to substitute one equation into another. That way, we can form an equation with only one variable in it. Let's put our first equation into the second one:

x+(3x−11)=69

From here, all we have to do is simplification:

x+3x−11=69

4x−11=69

4x=80

x=20

We have our smaller number, 20. To find the larger number, plug the smaller number into our second equation and solve for y:

20+y=69

y=49

We now have our larger number 49.

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