Find the slope of the line perpendicular to y=1/8x+7

Find the slope of the line perpendicular to $y=\frac{1}{8}x+7$
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xgirlrogueim
If 2 lines are perpendicular to each other then the product of their gradients is equal to -1 .
If gradients of 2 perpendicular lines are ${m}_{1}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}{m}_{2}$
then: ${m}_{1}×{m}_{2}=-1$
The equation $y=\frac{1}{8}x+7$
is of the form y = mx + c , where m represents the gradient and c , the y-intercept.
hence this line has $m=\frac{1}{8}$
m of perpendicular is found using the above relationship.
$\frac{1}{8}×{m}_{2}=-1⇒{m}_{2}=-\frac{1}{\frac{1}{8}}=-8$