# Find the slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2)

Find the slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2)
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Joel Reese
A line passing through (6,−1) and (3,2)
has a slope of
$m=\frac{\left(-1\right)-\left(-2\right)}{6-3}$
$=\frac{1}{3}$

If a line has slope m
then any line perpendicular to it has slope $\left(-\frac{1}{m}\right)$

The slope of a line perpendicular to the line passing through the given points P(6,-1) and Q(3,-2) is (−3)