# You have a triangle. angle A = 41 degrees, side b = 3.41 and c = 5.83.

Solving a triangle, given two sides and the measure of the included angle
Let say you have a triangle
$\mathrm{\angle }A={41}^{\circ }$, side $b=3.41$ and $c=5.83$
Can you use pythagoras theorem to find the side a? and how can you find Angle B and C
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Step 1
To find side a use Law Of Cosines: ${a}^{2}={b}^{2}+{c}^{2}-2\cdot b\cdot c\mathrm{cos}\alpha$
Step 2
To find angles $\beta$ and $\gamma$ use Sine Law: $\frac{a}{\mathrm{sin}\alpha }=\frac{b}{\mathrm{sin}\beta }=\frac{c}{\mathrm{sin}\gamma }$