What is the distance between (2,-6) and (4,-4)?

What is the distance between (2,-6) and (4,-4)?
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Kellen Blackburn
The distance formula for Cartesian coordinates is
$d=\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}}$
Where ${x}_{1},{y}_{1}$, and ${x}_{2},{y}_{2}$ are the Cartesian coordinates of two points respectively.Let $\left({x}_{1},{y}_{1}\right)$ represent (2,−6) and $\left({x}_{2},{y}_{2}\right)$ represent (4.−4).
$⇒d=\sqrt{{\left(4-2\right)}^{2}+{\left(-4-\left(-6\right)\right)}^{2}}$
$⇒d=\sqrt{4+{\left(2\right)}^{2}}$
$⇒d=\sqrt{4+4}$
$⇒d=\sqrt{8}$
$⇒d=2\sqrt{2}$
Hence the distance between the given points is $2\sqrt{2}$ units.