Distance between (5,12) and (10,2)?

Orion Cervantes
2022-09-25
Answered

Distance between (5,12) and (10,2)?

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Carina Moon

Answered 2022-09-26
Author has **6** answers

Let distance be d. Then

$\times}{d}^{2}={(\Delta x)}^{2}+{(\Delta y)}^{2}{\times \times \times \times \times x$ (Pythagorous' Theorem)

$\Rightarrow \sqrt{{d}^{2}}=\sqrt{{\left({{x}_{2}-{x}_{1}}\right)}^{2}+{\left({{y}_{2}-{y}_{1}}\right)}^{2}}$

$\Rightarrow d=\sqrt{{({10}-{5})}^{2}+{({2}-{12})}^{2}}$

$\times x}=\sqrt{{{5}}^{2}+{{10}}^{2}$

$\times x}=\sqrt{{25}+{100}$

$\times x}=5\sqrt{5$

$\times}{d}^{2}={(\Delta x)}^{2}+{(\Delta y)}^{2}{\times \times \times \times \times x$ (Pythagorous' Theorem)

$\Rightarrow \sqrt{{d}^{2}}=\sqrt{{\left({{x}_{2}-{x}_{1}}\right)}^{2}+{\left({{y}_{2}-{y}_{1}}\right)}^{2}}$

$\Rightarrow d=\sqrt{{({10}-{5})}^{2}+{({2}-{12})}^{2}}$

$\times x}=\sqrt{{{5}}^{2}+{{10}}^{2}$

$\times x}=\sqrt{{25}+{100}$

$\times x}=5\sqrt{5$

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