$(x-3)(x+7)=0$

1.$x=-3,x=7$

2. $x=-3,x=7$

3. $x=3,x=-7$

4.$x=-3;x=-7$

traffig75
2022-09-25
Answered

Solve by applying the zero product property.

$(x-3)(x+7)=0$

1.$x=-3,x=7$

2. $x=-3,x=7$

3. $x=3,x=-7$

4.$x=-3;x=-7$

$(x-3)(x+7)=0$

1.$x=-3,x=7$

2. $x=-3,x=7$

3. $x=3,x=-7$

4.$x=-3;x=-7$

You can still ask an expert for help

Rachael Conner

Answered 2022-09-26
Author has **8** answers

According to zero product property if $(x-a)(x-b)=0$

Then, $(x-a)=0$ or $(x-b)=0$ or both

Therefore,

$(x-3)(x+7)=0$

$\Rightarrow (x-3)=0,(x+7)=0$

$\Rightarrow x=3,x=-7$

Therefore, the correct answer is

$x=3,x=-7$

Then, $(x-a)=0$ or $(x-b)=0$ or both

Therefore,

$(x-3)(x+7)=0$

$\Rightarrow (x-3)=0,(x+7)=0$

$\Rightarrow x=3,x=-7$

Therefore, the correct answer is

$x=3,x=-7$

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