Find the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms

Find the sum of the arithmetic sequence 8, 14, 20 …, if there are 24 terms
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Ashlynn Delacruz
The sum to n terms of an arithmetic sequence is found by using
${S}_{n}=\frac{n}{2}\left[2a+\left(n-1\right)d\right]$
where a , is the first term and d , the common difference
here a = 8 and d = 14 - 8 = 20 - 14 =.......= 6
hence ${S}_{24}=\frac{24}{2}\left[\left(2×8\right)+\left(23×6\right)\right]$
= 12[ 16 + 138 ] = 12( 154) = 1848