# Rewrite the quadratic function in standard form. f(x)=x^2-10x+27

Rewrite the quadratic function in standard form.
$f\left(x\right)={x}^{2}-10x+27$
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devilvunga
Solution:
$f\left(x\right)={x}^{2}-10x+27\phantom{\rule{0ex}{0ex}}={x}^{2}-10x+25+2\phantom{\rule{0ex}{0ex}}=\left(x-5{\right)}^{2}+2\phantom{\rule{0ex}{0ex}}f\left(x\right)=\left(x-5{\right)}^{2}+2\phantom{\rule{0ex}{0ex}}f\left(x\right)-2=\left(x-5{\right)}^{2}$
vertex
$\left(x,y\right)=\left(5,2\right)$