$$x=\frac{7}{8},\text{}y=\frac{1}{4},\text{}z=\frac{5}{12}$$ Evaluate the variable expression x+ y + z for the given values of x, y and z.

Teagan Huffman
2022-09-27
Answered

$$x=\frac{7}{8},\text{}y=\frac{1}{4},\text{}z=\frac{5}{12}$$ Evaluate the variable expression x+ y + z for the given values of x, y and z.

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Trace Arias

Answered 2022-09-28
Author has **6** answers

$$x=\frac{7}{8},\text{}y=\frac{1}{4},\text{}z=\frac{5}{12}\phantom{\rule{0ex}{0ex}}x+y+z=\frac{7}{8}+\frac{1}{4}+\frac{5}{12}$$

To add fractions, make the denominators same.

Least common multiple of 8 , 4 and 12 is 24.

So making the denominator of each term 24,

$$x+y+z=\frac{7}{8}\cdot \frac{3}{3}+\frac{1}{4}\cdot \frac{6}{6}+\frac{5}{12}\cdot \frac{2}{2}\phantom{\rule{0ex}{0ex}}x+y+z=\frac{21}{24}+\frac{6}{24}+\frac{10}{24}=\frac{21+6+10}{24}=\frac{37}{24}\phantom{\rule{0ex}{0ex}}x+y+z=\frac{37}{24}$$

To add fractions, make the denominators same.

Least common multiple of 8 , 4 and 12 is 24.

So making the denominator of each term 24,

$$x+y+z=\frac{7}{8}\cdot \frac{3}{3}+\frac{1}{4}\cdot \frac{6}{6}+\frac{5}{12}\cdot \frac{2}{2}\phantom{\rule{0ex}{0ex}}x+y+z=\frac{21}{24}+\frac{6}{24}+\frac{10}{24}=\frac{21+6+10}{24}=\frac{37}{24}\phantom{\rule{0ex}{0ex}}x+y+z=\frac{37}{24}$$

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Divide or state that the division is undefined: (Note: If applicable, type your answer as a fraction, not as a decimal.)

A) -2/5 divide (- 3/4)

B) 3/0

A) -2/5 divide (- 3/4)

B) 3/0

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How to solve this? (adding polynomial fractions)

I'm having trouble solving this expression:

$\frac{(x-1)(7x+6)}{(x-1){(x+1)}^{2}}-\frac{7}{(x+1)}$

What's the steps to solve this?

I know you expand$(x+1)}^{2$ to $(x+1)(x+1)$

and that you need to find a common denominator before adding the numerators together.

The final answer is${\textstyle \phantom{\rule{1em}{0ex}}}\frac{-1}{{x}^{2}+2x+1}.$

Thanks.

I'm having trouble solving this expression:

What's the steps to solve this?

I know you expand

and that you need to find a common denominator before adding the numerators together.

The final answer is

Thanks.

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There are 3 salesmen A,B,C with the following turnovers

$A=2000\mathrm{\$}}$

$B=3000\mathrm{\$}}$

$C=5000\mathrm{\$}}$

Now, If the company wants to increase total turnover by 10 %, Should this be split as 10% for all salesmen OR Can 10% be split across A,B,C differently using weighted averages/percentages?

Let's say a Marketing company has a total turnover of 10000 $

There are 3 salesmen A,B,C with the following turnovers

Now, If the company wants to increase total turnover by 10 %, Should this be split as 10% for all salesmen OR Can 10% be split across A,B,C differently using weighted averages/percentages?

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Can someone please help me with this simple limit problem, I do not know what to do here because its undefined $0/0$

$\underset{x\to 0}{lim}\frac{{e}^{1/x}}{\sqrt{x}}.$

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How to show the following is true?

I need a proof of the following. If

$$\frac{{a}_{1}}{{b}_{1}}=\frac{{a}_{2}}{{b}_{2}}=\cdots =\frac{{a}_{K}}{{b}_{K}}=T$$

then

$$\frac{{a}_{i}}{{b}_{i}}=\frac{\sum _{i=1}^{K}{a}_{i}}{\sum _{i=1}^{K}{b}_{k}}$$

where all the ${a}_{i}$'s and ${b}_{i}$'s are positive values.

I need a proof of the following. If

$$\frac{{a}_{1}}{{b}_{1}}=\frac{{a}_{2}}{{b}_{2}}=\cdots =\frac{{a}_{K}}{{b}_{K}}=T$$

then

$$\frac{{a}_{i}}{{b}_{i}}=\frac{\sum _{i=1}^{K}{a}_{i}}{\sum _{i=1}^{K}{b}_{k}}$$

where all the ${a}_{i}$'s and ${b}_{i}$'s are positive values.

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