Please help me find the Inverse Laplace transform of:

$$F(s)=\frac{1}{s({s}^{2}+8s+4)}$$

After completing the square, I obtained

$$F(s)=\frac{1}{s((s+4{)}^{2}-12)}$$

$$F(s)=\frac{1}{s({s}^{2}+8s+4)}$$

After completing the square, I obtained

$$F(s)=\frac{1}{s((s+4{)}^{2}-12)}$$