Find the exact value of arcsec(sqrt 2)

Find the exact value of $\text{arcsec}\left(-\sqrt{2}\right)$
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Solution:
$\mathrm{sec}\left(\pi -\frac{\pi }{4}\right)\phantom{\rule{0ex}{0ex}}=\mathrm{sec}\left(-\frac{\pi }{4}\right)\phantom{\rule{0ex}{0ex}}=-\sqrt{2}\phantom{\rule{0ex}{0ex}}\mathrm{sec}\left(\pi -\frac{\pi }{4}\right)=\mathrm{sec}\left(\frac{3\pi }{4}\right)=-\sqrt{2}\phantom{\rule{0ex}{0ex}}\therefore \text{arcsec}\left(-\sqrt{2}\right)=\frac{3\pi }{4}$