A gondola on an amusement park ride, similar to the Spin Cycle at Silverwood Theme Park, spins at a speed of 13 revolutions per minute. If the gondola is 25 feet from the ride's center, what is the linear speed of the gondola in miles per hour?

iohanetc

iohanetc

Answered question

2021-02-18

A gondola on an amusement park ride, similar to the Spin Cycle at Silverwood Theme Park, spins at a speed of 13 revolutions per minute. If the gondola is 25 feet from the ride's center, what is the linear speed of the gondola in miles per hour?

Answer & Explanation

cheekabooy

cheekabooy

Skilled2021-02-19Added 83 answers

The relationship of the linear speed vv to the angular speed ω (in radians per unit time) and radius r is:
v=ωr
Convert the angular speed to radians per hour:
ω=(13revmin)(2πrad1rev)(60min1hr)=1560πradhr
Convert the radius to miles:
r=25ft(1mi5280ft)=255280mis
So, the linear speet is:
v=1560πradhr(255280)mis
v23.2mihr

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