# How do you solve the differential dy/dx=x−4/√x^2−8x+1?

How do you solve the differential $\frac{dy}{dx}=\frac{x-4}{\sqrt{{x}^{2}-8x+1}}$?
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Lilia Horton
$\frac{dy}{dx}=\frac{x-4}{\sqrt{{x}^{2}-8x+1}}$

Is a First Order separable DE which we can sole by integrating:

Let $u={x}^{2}-8x+1⇒\frac{du}{dx}=2x-8=2\left(x-4\right)$

Substituting into the RHS integral we get:

which is the General Solution