# Find the slope of a line perpendicular to the line whose equation is 5x+3y=8

Find the slope of a line perpendicular to the line whose equation is 5x+3y=8
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ahem37
If a line has slope =m
then the slope of a line perpendicular to it is $\left(-\frac{1}{m}\right)$

Rewrite $5x+3y=8$ in a slope-offset format

$y=-\frac{5}{3}x+\frac{8}{3}$
So the given equation has a slope of $\left(-\frac{5}{3}\right)$
and
a line perpendicular to it has a slope of $\left(\frac{3}{5}\right)$