How do you find the zeros of the function f(x)=(20x^2+11x−40)/(2x+5)?

Camila Brandt 2022-09-26 Answered
How do you find the zeros of the function f ( x ) = 20 x 2 + 11 x - 40 2 x + 5 ?
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Answers (1)

Simeon Hester
Answered 2022-09-27 Author has 16 answers
the denominator of f(x) cannot be zero as this would make f(x) undefined
the zeros are found by equating the numerator to zero
solve 20 x 2 + 11 x - 40 = 0 standard form
solve using the quadratic formula
with a=20,b=11 and c=−40
x x = - b ± b 2 - 4 a c 2 a
x = - 11 ± 121 + 3200 40
x = - 11 ± 3321 40 = - 11 ± 9 41 40
x = - 11 40 ± 9 41 40
x = - 11 40 - 9 41 40 or x = - 11 40 + 9 41 40
zeros are x - 1.72 , x 1.17 to 2 dec. places
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