# The number of atoms in 1 kg of carbon is given by =(12×1000)/(N_A), but if I remember correctly the number of atoms is equal to the number of moles times the Avogadro's number and hence should be =(1000×N_A)/12? It does a similar thing for the number of atoms in 1 kg of Uranium -235, which is given to be in the solution =(235×1000)/(N_A), and not =(1000×N_A)/235

The number of atoms in of carbon is given by $=\frac{12×1000}{{N}_{A}}$, but if I remember correctly the number of atoms is equal to the number of moles times the Avogadro's number and hence should be $=\frac{1000×{N}_{A}}{12}?$? It does a similar thing for the number of atoms in of Uranium $-235$, which is given to be in the solution $=\frac{235×1000}{{N}_{A}}$, and not $=\frac{1000×{N}_{A}}{235}$
So which is the correct answer?
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Triston Donaldson
${n}_{moles}=1000gm/\left(12gm/mole\right)$
so
${n}_{atom}=1000×{N}_{A}/12$