kakvoglq

2022-09-22

How do you graph $f\left(x\right)=\frac{3}{x+1}-2$ using holes, vertical and horizontal asymptotes, x and y intercepts?

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Jane Acosta

Expert

As you can see, there is a vertical asymptote at about y=1(because you can never get 1 out of this equation), and a horizontal asymptote at about x=−1 (because plugging in −1 for x creates a fraction with zero on the bottom, specifically $\frac{3}{0}$). There is an x-intercept at $y=\frac{1}{2}$, and a y-intercept at x=1. There are no holes.
graph{3/(x+1)-2 [-10, 10, -5, 5]}

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