Let the adjacent angles be $2x$

Let the other angle be $y$

Accordingly, $y=6/5\ast 2x$

What is next?

Elias Heath
2022-09-22
Answered

In a parallelogram, one angle is $2/5th$ of the adjacent angles. Determine the angles of the parallelogram.

Let the adjacent angles be $2x$

Let the other angle be $y$

Accordingly, $y=6/5\ast 2x$

What is next?

Let the adjacent angles be $2x$

Let the other angle be $y$

Accordingly, $y=6/5\ast 2x$

What is next?

You can still ask an expert for help

Lorenzo Acosta

Answered 2022-09-23
Author has **13** answers

You have the following equations. First, if we call $x$ and $y$ the different angles that you can find in the parallelogram.

$$2x+2y=360$$

And then the relation between $x$ and $y$ reads:

$$\frac{2x}{5}=y$$

You can get the answer from here.

$$x=\frac{900}{7}\phantom{\rule{2em}{0ex}}y=\frac{360}{7}$$

$$2x+2y=360$$

And then the relation between $x$ and $y$ reads:

$$\frac{2x}{5}=y$$

You can get the answer from here.

$$x=\frac{900}{7}\phantom{\rule{2em}{0ex}}y=\frac{360}{7}$$

Adrien Jordan

Answered 2022-09-24
Author has **1** answers

In a parallelogram, addition of $$2$$ adjacent angles always produces $\pi $. If any of the adjacent angles(the angles to the clockwise and the anti-clockwise direction to any angle $\mathrm{\angle}A$ are mutually equal) is x, then the angle in question is $$\frac{2x}{5}$$.

asked 2020-10-28

asked 2022-04-04

Solve for f and g: $\{\begin{array}{l}3f+5g=-5\\ 6f+5g=7\end{array}$

asked 2022-08-27

Flying to Kampala with a tailwind a plane averaged 158 km/h. On the return trip the plane only averaged 112 km/h while flying back into the same wind. Find the speed of the wind and the speed of the plane in still air.

asked 2022-06-15

solve the following linear system

${x}_{1}-3{x}_{2}+{x}_{3}=1$

$2{x}_{1}-{x}_{2}-2{x}_{3}=2$

${x}_{1}+2{x}_{2}-3{x}_{3}=-1$

by using gauss-jordan elimination method. The augmented matrix of the linear system is

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 2& -1& -2& 2\\ 1& 2& -3& -1\end{array}\right).$

By a series of elementary row operations, we have

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right).$

My question is, although the question asked us to solve the linear system using gauss-jordan elimination method, can we stop immediately and conclude that the linear system is inconsistent without further apply any elementary row operation to the matrix

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right)$

until the matrix

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right)$

is transformed into reduced-row echelon form?

${x}_{1}-3{x}_{2}+{x}_{3}=1$

$2{x}_{1}-{x}_{2}-2{x}_{3}=2$

${x}_{1}+2{x}_{2}-3{x}_{3}=-1$

by using gauss-jordan elimination method. The augmented matrix of the linear system is

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 2& -1& -2& 2\\ 1& 2& -3& -1\end{array}\right).$

By a series of elementary row operations, we have

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right).$

My question is, although the question asked us to solve the linear system using gauss-jordan elimination method, can we stop immediately and conclude that the linear system is inconsistent without further apply any elementary row operation to the matrix

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right)$

until the matrix

$\left(\begin{array}{cccc}1& -3& 1& 1\\ 0& 5& -4& 0\\ 0& 0& 0& -2\end{array}\right)$

is transformed into reduced-row echelon form?

asked 2022-07-01

I understood that two systems of linear equations are equivalent if one can be obtained by the linear combination of the other system and vice versa. But can those two systems of equations be equivalent even if the solution ${x}_{i}=0?(1\le i\le n)$.Example set:

${x}_{1}-{x}_{2}=0;$

$2{x}_{1}+{x}_{2}=0$

and

$3{x}_{1}+{x}_{2}=0;$

${x}_{1}+{x}_{2}=0$

Are these systems of equations equivalent?

${x}_{1}-{x}_{2}=0;$

$2{x}_{1}+{x}_{2}=0$

and

$3{x}_{1}+{x}_{2}=0;$

${x}_{1}+{x}_{2}=0$

Are these systems of equations equivalent?

asked 2022-06-11

I'm trying to solve a systems of equations problem but I can't seem to see what I'm doing wrong... As far as I can tell the way to solve a system of equations by substitution involves the following steps.

1. Isolate a variable in one of the equations

2. substitute that isolated variable into equation two so that you're second equation is in one variable

3. solve equation two for the second unknown variable

4. use the result from the second equation to find out what your original isolated variable equals.

here's my problem and what I tried:

equation 1: $1=A+B$

equation 2: $8=5A+2B$

Isolating $B$

$B=1-A$

Solving for $A$

$8=5A+2(1-A)$

$\Rightarrow 8=5A+2-2A$

$\Rightarrow 8=3A+2$

$\Rightarrow 6=3A$

$\Rightarrow A=1/2$

substituting back for $B$

$\Rightarrow B=1-1/2$

$\Rightarrow B=1/2$

final answer: $(A,B)=(1/2,1/2)$

can anyone tell me where I went wrong?

1. Isolate a variable in one of the equations

2. substitute that isolated variable into equation two so that you're second equation is in one variable

3. solve equation two for the second unknown variable

4. use the result from the second equation to find out what your original isolated variable equals.

here's my problem and what I tried:

equation 1: $1=A+B$

equation 2: $8=5A+2B$

Isolating $B$

$B=1-A$

Solving for $A$

$8=5A+2(1-A)$

$\Rightarrow 8=5A+2-2A$

$\Rightarrow 8=3A+2$

$\Rightarrow 6=3A$

$\Rightarrow A=1/2$

substituting back for $B$

$\Rightarrow B=1-1/2$

$\Rightarrow B=1/2$

final answer: $(A,B)=(1/2,1/2)$

can anyone tell me where I went wrong?

asked 2022-03-23

Let $A=\{0,1,2,3,4,5,6,7,8,9,10\}{\textstyle \phantom{\rule{1em}{0ex}}}\text{and}{\textstyle \phantom{\rule{1em}{0ex}}}$

$R=\{r\left({x}_{1}y\right):7)(2x+5y)$ where $x}_{1}y\u03f5A\$

Phase that R is an equivalence relation on A!

Phase that R is an equivalence relation on A!