# An airplane flies an altitude of 38,000 feet. As it nears the airport, the plane begins to descent at a rate of 600 feet per minute. At this rate, how many minutes will the plane take to descent to 18,800 feet?

An airplane flies an altitude of 38,000 feet. As it nears the airport, the plane begins to descent at a rate of 600 feet per minute. At this rate, how many minutes will the plane take to descent to 18,800 feet?
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Malcolm Flores
Altitude descended 38000−18800=19200ft
Descent rate (vertical speed) = 600ft/min
$\text{speed}=\frac{\text{distance}}{\text{time}}$
so $\text{time}=\frac{\text{distance}}{\text{speed}}$
$t=\frac{19200}{600}=32$