An airplane flies an altitude of 38,000 feet. As it nears the airport, the plane begins to descent at a rate of 600 feet per minute. At this rate, how many minutes will the plane take to descent to 18,800 feet?

gaby131o
2022-09-25
Answered

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Malcolm Flores

Answered 2022-09-26
Author has **8** answers

Altitude descended 38000−18800=19200ft

Descent rate (vertical speed) = 600ft/min

$\text{speed}=\frac{\text{distance}}{\text{time}}$

so $\text{time}=\frac{\text{distance}}{\text{speed}}$

$t=\frac{19200}{600}=32$

Descent rate (vertical speed) = 600ft/min

$\text{speed}=\frac{\text{distance}}{\text{time}}$

so $\text{time}=\frac{\text{distance}}{\text{speed}}$

$t=\frac{19200}{600}=32$

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