# Let f(x)=4x−3. Evaluate and simplify f(2+h).

Let $f\left(x\right)=4x-3$. Evaluate and simplify $f\left(2+h\right)$.
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Solve:
$f\left(x\right)=4x-3\phantom{\rule{0ex}{0ex}}f\left(2+x\right)=4\left(2+x\right)-3\phantom{\rule{0ex}{0ex}}=4\cdot 2+4\cdot h-3\phantom{\rule{0ex}{0ex}}=8+4h-3\phantom{\rule{0ex}{0ex}}=5+4h$