# Find coordinates of the vertex for the quadratic function f(x) = –22 - 4x + 8.

Find coordinates of the vertex for the quadratic function
$f\left(x\right)=–22-4x+8$
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Denier5h
$f\left(x\right)=-{x}^{2}-4x+8$
General form: $f\left(x\right)=a{x}^{2}+bx+c$
To get the vertex of quadratic
$h=\frac{-b}{2a}\phantom{\rule{0ex}{0ex}}k=f\left(h\right)$
Here $h=-\frac{\left(-4\right)}{2\left(-1\right)}=-2\phantom{\rule{0ex}{0ex}}k=f\left(-2\right)=-\left(-2{\right)}^{2}-4\left(-2\right)+8\phantom{\rule{0ex}{0ex}}k=12\phantom{\rule{0ex}{0ex}}$
vertex form $=a\left(x-h{\right)}^{2}+k\phantom{\rule{0ex}{0ex}}=-\left(x+2{\right)}^{2}+12$