How do you find a_13 given a_n=4n^2−n+3/n(n−1)(n+2)?

Liberty Page 2022-09-23 Answered
How do you find a 13 given a n = 4 n 2 - n + 3 n ( n - 1 ) ( n + 2 ) ?
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Answers (1)

edytorialkp
Answered 2022-09-24 Author has 10 answers
a n = 4 n 2 - n + 3 n ( n - 1 ) ( n - 2 )
a 13 = 4 ( 13 ) 2 - 13 + 3 13 ( 13 - 1 ) ( 13 - 2 )
= 4 169 - 10 156 ( 11 )
= 666 1716
= 111 286
= 0.3 881118 ¯
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