Anthony left home 2 hours before Greg. Both boys were traveling to see their grandmother in New York. Anthony drove at 50 mph and greg drove 65 mph. So how long did it take greg to catch up with Anthony?

memLosycecyjz
2022-09-22
Answered

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kregde84

Answered 2022-09-23
Author has **10** answers

Let t represent time in hours, using t=0 to represent the time Greg set out.

At time $t\ge 0$ Anthony will have travelled 50(t+2) miles and Greg 65t miles.

Greg will catch up with Anthony when 65t=50(t+2)

65t=50(t+2)=50t+100

Subtract 50t from both ends to get:

15t=100

Divide both sides by 15 to get

$t=\frac{100}{15}=\frac{90}{15}+\frac{10}{15}=6+\frac{2}{3}=6$ hours, 40 minutes.

At time $t\ge 0$ Anthony will have travelled 50(t+2) miles and Greg 65t miles.

Greg will catch up with Anthony when 65t=50(t+2)

65t=50(t+2)=50t+100

Subtract 50t from both ends to get:

15t=100

Divide both sides by 15 to get

$t=\frac{100}{15}=\frac{90}{15}+\frac{10}{15}=6+\frac{2}{3}=6$ hours, 40 minutes.

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