How do you graph f(x)=(5−2x)/(x−2) using holes, vertical and horizontal asymptotes, x and y intercepts?

furajat4h 2022-09-24 Answered
How do you graph f ( x ) = 5 - 2 x x - 2 using holes, vertical and horizontal asymptotes, x and y intercepts?
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Answers (1)

Kaya Garza
Answered 2022-09-25 Author has 8 answers
Rearrange.
y = 5 - 2 x x - 2 = - 2 ( x - 2 ) + 1 x - 2 = - 2 + 1 x - 2

This means that x=2 and y=−2 are horizontal and vertical asymptotes.

Subbing x=0 to find the y-intercept, we have - 2 + 1 0 - 2 = - 5 2 so ( 0 , - 5 2 )

Subbing y=0 to find the x-intercept, we have 0 = 5 - 2 x x - 2
x = 5 2 so ( 5 2 , 0 )

Plot your intercepts and draw your asymptotes and you should have a general idea of how your graph looks.
graph{(5-2x)/(x-2) [-10, 10, -5, 5]}
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