Complete the steps to solve the division problem using long division. $$x+1\sqrt{2{x}^{2}+x-1}$$

Lustyku8
2022-09-23
Answered

Complete the steps to solve the division problem using long division. $$x+1\sqrt{2{x}^{2}+x-1}$$

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Edgeriecoereexq

Answered 2022-09-24
Author has **4** answers

The algorithm in polynomial division is very similar in dividing numbers.

First, we divide $$2{x}^{2}$$ by x, the first terms of the dividend and divisor, respectively to obtain 2x and will be the first term of the quotient. Multiply 2x by x+1 to obtain $$2{x}^{2}+2x$$ which will be subtracted from $$2{x}^{2}-2x$$ to obtain a remainder of -x and bring down -1.

Then, we divide -x by x (from the divisor), to obtain -1 which will be the second term of the quotient. Multiply -1 by x+1 to obtain -x-1 which will be subtracted from -x-1 to obtain a remainder of 0. The quotient is 2x-1.

Result:

2x-1

First, we divide $$2{x}^{2}$$ by x, the first terms of the dividend and divisor, respectively to obtain 2x and will be the first term of the quotient. Multiply 2x by x+1 to obtain $$2{x}^{2}+2x$$ which will be subtracted from $$2{x}^{2}-2x$$ to obtain a remainder of -x and bring down -1.

Then, we divide -x by x (from the divisor), to obtain -1 which will be the second term of the quotient. Multiply -1 by x+1 to obtain -x-1 which will be subtracted from -x-1 to obtain a remainder of 0. The quotient is 2x-1.

Result:

2x-1

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