Let C[0,1] be the space of continuous functions [0,1]->R endowed with the norm ||x||_infty=max_t in [0,1]| x(t)|. It is easy to verify that this norm is not induced by any inner product (really the parallelogram law fails for x(t)=t and y(t)=1). Well, how to understand that this norm is not equivalent to anyone induced by an inner product? So, the norms induced by inner products should have some special properties...

Addyson Bright

Addyson Bright

Answered question

2022-09-22

Let C[0,1] be the space of continuous functions [ 0 , 1 ] R endowed with the norm | | x | | = m a x t [ 0 , 1 ] | x ( t ) | . It is easy to verify that this norm is not induced by any inner product (really the parallelogram law fails for x(t)=t and y(t)=1). Well, how to understand that this norm is not equivalent to anyone induced by an inner product? So, the norms induced by inner products should have some special properties...

Answer & Explanation

Zariah Fletcher

Zariah Fletcher

Beginner2022-09-23Added 8 answers

pointed out this particular norm is not equivalent to norm induced by inner product because C([0,1]) is not reflexive. But reflexivity is not enough for space to be Hilbertable.
One can suggest that being isomorphic to its dual is enough, but X 2 X with reflexive X gives a bunch of counterexamples.
Characterisation in terms of geometry of Banach spaces was given by Lindenstrauss and Tzafriri: Banach space X is isomorphic to Hilbert space iff every closed subspace of X is complemented (i. e.the range of some bounded projection).

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