Camila Brandt
2022-09-22
Answered

A ball starts at rest atop a 4 m tall pillar. The ball falls from the pillar and reaches the ground. The initial state is the ball on the pillar. The final state is the ball just before it makes contact with the ground. Ignore air resistance, what is the speed of the ball when it reaches the ground?

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ruinsraidy4

Answered 2022-09-23
Author has **17** answers

here,

the height of ball above the pillar , h = 4 m

the speed of the ball when it reaches the ground , $v=\sqrt{(2\cdot g\cdot h)}$

$v=\sqrt{(2\cdot 9.8\cdot 4)}m/s$

$v=8.85m/s$

the speed of the ball when it reaches the ground is 8.85 m/s

the height of ball above the pillar , h = 4 m

the speed of the ball when it reaches the ground , $v=\sqrt{(2\cdot g\cdot h)}$

$v=\sqrt{(2\cdot 9.8\cdot 4)}m/s$

$v=8.85m/s$

the speed of the ball when it reaches the ground is 8.85 m/s

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