# How do you write the equation y−5=6(x+1) in slope intercept form?

How do you write the equation $y-5=6\left(x+1\right)$ in slope intercept form?
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devilvunga
The slope-intercept form of a linear equation is: y=mx+b
Where m is the slope and b is the y-intercept value.
First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis:
$y-5=6\left(x+1\right)$
$y-5=\left(6×x\right)+\left(6×1\right)$
$y-5=6x+6$
Now, add 5 to each side of the equation to solve for y while keeping the equation balanced:
$y-5+5=6x+6+5$
$y-0=6x+11$
$y=6x+11$
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