# How do you write an equation in standard form for a line with a slope of 1/4 and goes through point (4, 0)?

How do you write an equation in standard form for a line with a slope of 1/4 and goes through point (4, 0)?
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Kelbelol
the equation of a line in standard form is.
$\overline{\underline{|\frac{2}{2}Ax+By=C\frac{2}{2}|}}$
where A is a positive integer and B, C are integers
to begin express the equation in point-slope form
$•xy-{y}_{1}=m\left(x-{x}_{1}\right)$
$\text{where m is the slope and}\phantom{\rule{1ex}{0ex}}\left({x}_{1},{y}_{1}\right)\phantom{\rule{1ex}{0ex}}\text{a point on the line}$
$\text{here}\phantom{\rule{1ex}{0ex}}m=\frac{1}{4}\phantom{\rule{1ex}{0ex}}\text{and}\phantom{\rule{1ex}{0ex}}\left({x}_{1},{y}_{1}\right)=\left(4,0\right)$
$⇒y=\frac{1}{4}\left(x-4\right)$
$⇒y=\frac{1}{4}x-1$
multiply all terms by 4
$⇒4y=x-4$
$⇒x-4y=4←\text{in standard form}$