Let f(x)=ln(x)/sqrtx. Find the critical values of f(x).

misyjny76 2022-09-20 Answered
Let f ( x ) = ln ( x ) x . Find the critical values of f(x)
How would you find the critical value of this equation? So far... I have gotten that you find the derivative of f(x) which is f ( x ) = 1 x 3 / 2 ln ( x ) 2 x 3 / 2 ..
To find the critical values set f ( x ) = 0? But how would you factor out the derivative to find the critical values?
Also, after that how would you find the intervals of increase and decrease and relative extreme values of f(x).
And lastly the intervals of concavity and inflection points.
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Answers (2)

wayiswa8i
Answered 2022-09-21 Author has 6 answers
Explanation:
Since f ( x ) = 2 ln x x 3 / 2 , f ( x ) = 0 x = e 2 . Furthermore, f ( x ) < 0 when x > e 2 and f ( x ) > 0 when 0 < x < e 2
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Julia Chang
Answered 2022-09-22 Author has 2 answers
Explanation:
Rewrite f′ as f ( x ) = 1 1 / 2 ln x x 3 / 2 and to find f = 0 you need to find when 1 1 / 2 ln x = 0 ln x = 2.
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