# Distance between (2,8) and (-6,-7)?

Distance between (2,8) and (-6,-7)?
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Lorenzo Acosta
$\left(2,8\right)={x}_{1},{y}_{1}$
$\left(-6,-7\right)={x}_{2},{y}_{2}$
The distance is calculated using formula:
Distance $=\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}}$
$=\sqrt{{\left(-6-2\right)}^{2}+{\left(-7-8\right)}^{2}}$
$=\sqrt{{\left(-8\right)}^{2}+{\left(-15\right)}^{2}}$
$=\sqrt{289}$
$=17$
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