Write the first six terms of the sequence $a}_{n}={(n-1)}^{2$

lunja55
2022-09-22
Answered

Write the first six terms of the sequence $a}_{n}={(n-1)}^{2$

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cercimw

Answered 2022-09-23
Author has **8** answers

You can derive the $n}^{th$ term by puuting the value of n in $a}_{n}={(n-1)}^{2$

Hence, ${a}_{1}={(1-1)}^{2}=0$

${a}_{2}={(2-1)}^{2}={1}^{2}=1$

${a}_{3}={(3-1)}^{2}={2}^{2}=4$

${a}_{4}={(4-1)}^{2}={3}^{2}=9$

${a}_{5}={(5-1)}^{2}={4}^{2}=16$

${a}_{6}={(6-1)}^{2}={5}^{2}=25$

Hence, first six terms are {0,1,4,9,16,25}

Hence, ${a}_{1}={(1-1)}^{2}=0$

${a}_{2}={(2-1)}^{2}={1}^{2}=1$

${a}_{3}={(3-1)}^{2}={2}^{2}=4$

${a}_{4}={(4-1)}^{2}={3}^{2}=9$

${a}_{5}={(5-1)}^{2}={4}^{2}=16$

${a}_{6}={(6-1)}^{2}={5}^{2}=25$

Hence, first six terms are {0,1,4,9,16,25}

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