# A machinist creates a washer by drilling a hole through the center of a circular piece of metal. If the piece of metal has a radius of x + 10 and the hole has a radius of x + 6, what is the area of the washer?

A machinist creates a washer by drilling a hole through the center of a circular piece of metal. If the piece of metal has a radius of x + 10 and the hole has a radius of x + 6, what is the area of the washer?
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gerasseltd9
Area of the Circle$=\pi {r}^{2}$
Area of the washer
$=\pi \left({\left(x+10\right)}^{2}-{\left(x+6\right)}^{2}\right)$
$=\pi \left(x+10+x+6\right)\left(x+10-x-6\right)$
$=\pi \left(2x+16\right)\left(10-6\right)$
$=8\pi \left(x+8\right)$