What is the x intercept of $y=-\frac{6}{5}x+6$?

easternerjx
2022-09-23
Answered

What is the x intercept of $y=-\frac{6}{5}x+6$?

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Firetto8w

Answered 2022-09-24
Author has **8** answers

$y=-\frac{6}{5}x+6$

The x-intercept is the value of x when y is zero.

Substitute 0 for y in the equation.

$0=-\frac{6}{5}x+6$

Subtract 6 from both sides of the equation.

$-6=-\frac{6}{5}x+6-6=$

$-6=-\frac{6}{5}x$

Divide by $-\frac{6}{5}$ on both sides. When dividing by a fraction, multiply times its reciprocal.

$-\overline{){6}^{1}}(-\frac{5}{{\overline{)6}}^{1}})=-\frac{{\overline{)6}}^{1}}{{\overline{)5}}^{1}}x(-\frac{{\overline{)5}}^{1}}{{\overline{)6}}^{1}})$

5=x

Switch sides.

x=5

The x-intercept is the value of x when y is zero.

Substitute 0 for y in the equation.

$0=-\frac{6}{5}x+6$

Subtract 6 from both sides of the equation.

$-6=-\frac{6}{5}x+6-6=$

$-6=-\frac{6}{5}x$

Divide by $-\frac{6}{5}$ on both sides. When dividing by a fraction, multiply times its reciprocal.

$-\overline{){6}^{1}}(-\frac{5}{{\overline{)6}}^{1}})=-\frac{{\overline{)6}}^{1}}{{\overline{)5}}^{1}}x(-\frac{{\overline{)5}}^{1}}{{\overline{)6}}^{1}})$

5=x

Switch sides.

x=5

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