# What is the distance between (22,25,7) and (31,40,0)?

What is the distance between (22,25,7) and (31,40,0)?
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altaryjny94
The distance between $\left({x}_{1},{y}_{1},{z}_{1}\right)$ and $\left({x}_{2},{y}_{2},{z}_{2}\right)$ is given by
$\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}+{\left({z}_{2}-{z}_{1}\right)}^{2}}$
So for these two points we have:
$\sqrt{{\left(31-22\right)}^{2}+{\left(40-25\right)}^{2}+{\left(0-7\right)}^{2}}=\sqrt{{\left(9\right)}^{2}+{\left(15\right)}^{2}+{\left(-7\right)}^{2}}=\sqrt{81+225+49}=\sqrt{355}\approx 18.8$
$\sqrt{{\left(31-22\right)}^{2}+{\left(40-25\right)}^{2}+{\left(0-7\right)}^{2}}=\sqrt{{\left(9\right)}^{2}+{\left(15\right)}^{2}+{\left(-7\right)}^{2}}=\sqrt{81+225+49}=\sqrt{355}\approx 18.8$